One year ago a man was eight times old as his son . Now his age is equal to the square of his son's age . Represent this situation in form of a quadratic equation

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Solution

Let the present age of man be $x^{2}$
His son age is $x$
One year ago, his age is $x^{2} - 1$
His son age is $x - 1$
According to question
$x^{2} - 1 = 8 (x - 1) x^{2} - 8 x + 7 = 0$

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One year ago a man was eight times old as his son . Now his age is equal to the square of his son's age . Represent this situation in form of a quadratic equation

Let the present age of man be x2His son age is xOne year ago, his age is x2−1His son age is x−1According to question x2−1=8(x−1)x2−8x+7=0

Let the present age of man be $x^{2}$
His son age is $x$
One year ago, his age is $x^{2} - 1$
His son age is $x - 1$
According to question
$x^{2} - 1 = 8 (x - 1) x^{2} - 8 x + 7 = 0$