Ones digit in the cube of $38$ is _________.

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Solution

In $38$ , One's place digit is $" 8 "$ .
Cube of $" 8 " = 8^{3} = 512$
Here we get digit at one's place is $" 2 " .$
Therefore, digit at one's place of cube of $38$ is $" 2 " .$

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State true or false.

(i) Cube of any odd number is even.

(ii) A perfect cube does not end with two zeroes.

(iii) If square of a number ends with 5, then its cube ends with 25.

(iv) There is no perfect cube which ends with 8.

(v) The cube of a two digit number may be a three digit number.

(vi) The cube of a two digit number may have seven or more digits.

(vii) The cube of a single digit number may be a single digit number.

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