The correct option is A 6x + 5y = 12000We know the total votes cast were 1200. So, nbsp; 60 ...

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Standard IX

Mathematics

Solution of a Single Linear Equation in Two Variables

Only 60

Question

Only 60% and 50% of eligible voters of town A and B respectively, cast their vote in the election. The total number of votes cast were $1200.$
Which of the following linear equations represents this scenario accurately?
(Assume number of eligible voters in town A to be $x$ and in town B to be $y$ )

5 x + 6 y = 12000

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6 x + 5 y = 12000

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5 x + 6 y = 1200

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6 x + 5 y = 1200

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Solution

The correct option is B $6 x + 5 y = 12000$
We know the total votes cast were $1200$ . So, 60% of $x$ and 50% of $y$ should be equal to $1200.$
$⟹ (\frac{60}{100} \times x) + (\frac{50}{100} \times y) = 1200 ⟹ 6 x + 5 y = 12000$

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In an electio n 60% of voters cast their votes. From an equation and draw the graph with this data.read From the graph. The total number of voters if2100 voters cast their votes.the number of votes cast if the total number of voters are1000 .

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Only 60% and 50% of eligible voters of town A and B respectively, cast their vote in the election. The total number of votes cast were 1200. Which of the following linear equations represents this scenario accurately? (Assume number of eligible voters in town A to be x and in town B to be y)

The correct option is B 6x+5y=12000We know the total votes cast were 1200. So, 60% of x and 50% of y should be equal to 1200. ⟹(60100×x)+(50100×y)=1200⟹6x+5y=12000

Only 60% and 50% of eligible voters of town A and B respectively, cast their vote in the election. The total number of votes cast were $1200.$
Which of the following linear equations represents this scenario accurately?
(Assume number of eligible voters in town A to be $x$ and in town B to be $y$ )

The correct option is B $6 x + 5 y = 12000$
We know the total votes cast were $1200$ . So, 60% of $x$ and 50% of $y$ should be equal to $1200.$
$⟹ (\frac{60}{100} \times x) + (\frac{50}{100} \times y) = 1200 ⟹ 6 x + 5 y = 12000$