Question

Orbital angular momentum of an electron in a particular subshell is $\sqrt{5}\frac{h}{\pi }$ . Then find the maximum number of electrons which may be present in this subshell.

• A. 18
• B. 24
• C. 16
• D. 8

Answer 1

The correct option is A 18

Orbital angular momentum is $\sqrt{l(l+1)}\frac{h}{2\pi }=\sqrt{5}\frac{h}{\pi }$

now equating both,

$\sqrt{l(l+1)}=2\sqrt{5}$
$\sqrt{l(l+1)}=2\sqrt{5}$ = \sqrt{20}\)
$l(l+1)=20$
so, $l=4$

The maximum no. of electrons = $2(2l+1)=2\times 9=18$