Question

Orbital angular momentum of an electron is $\sqrt{3}\frac{h}{\pi }$. Then, the possible number of orientations of this orbital in space are:

• A. 3
• B. 5
• C. 7
• D. 9

Answer 1

Answer: (C)

7

Orbital angular momentum of an electron is $\sqrt{3}\frac{h}{\pi }$.

Orbital angular momentum of electron is given by:

$⟹\sqrt{l(l+1)}\frac{h}{2\pi }\Rightarrow \sqrt{l(l+1)}\frac{h}{2\pi }=\sqrt{3}\frac{h}{\pi }\Rightarrow l=3$

$\therefore$ Number of orientations $=2l+1=2$ X $3+1=7$.

Option C is correct.