Question

Orbital having 3 angular nodes and 3 total nodes is

• A. $5p$
• B. $3d$
• C. $4f$
• D. $6d$

Answer 1

The correct option is C $4f$

Orbital having angular node $\left(l\right)=3$
$\text{Total node = Radial node + angular node}=n-l-1+l$
$3=n-1$
$n=4$
Hence,subshell:
$nl=4f$