Order and degree of -1- d2ydx2 3- 2-dydx 1-3 is-

The correct option is B 2, 9 ⇒ [ 1+ ( d^2ydx^2 )^3 ]^3=(2+y_1)^2 (1+y_2^3)^3=(2+y_1)^2 ⇒ y_2^9+1+3y_2^3(1+y_2^3)=4+4y_1+y_1^2 ⇒ Order ...

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Degree of a Differential Equations

Order and deg...

Question

Order and degree of $\sqrt{1 + {(\frac{d^{2} y}{d x^{2}})}^{3}} = {(2 + \frac{d y}{d x})}^{1 / 3}$ is:

2, 3

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2, 9

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2, 6

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2, 2

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\sqrt{1 + {(\frac{d^{2} y}{d x^{2}})}^{3}} = {(2 + \frac{d y}{d x})}^{1 / 3}

{(\frac{d y}{d x})}^{3} + 5 x = {(\frac{d^{2} y}{d x^{2}})}^{3 / 2}

x^{2} = \frac{{(1 + {(\frac{d y}{d x})}^{2})}^{3 / 2}}{\frac{d^{2} y}{d x^{2}}}

y = 1 + {(\frac{d y}{d x})}^{1} + \frac{1}{2!} {(\frac{d y}{d x})}^{2} + \frac{1}{3!} {(\frac{d y}{d x})}^{3} + . . . . .

\frac{d^{2} y}{d x^{2}} = x l o g (\frac{d y}{d x})

\frac{{(1 + {(\frac{d y}{d x})}^{2})}^{\frac{3}{2}}}{\frac{d^{2} y}{d x^{2}}} = c

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