Order and degree of the D-E - dydx 2-d2ydx2 -3-4-Kd3ydx3 is-

The correct option is D 3,4 [y_1^2+ y_2]^3=ky_3^4 ⇒ Order=3 degree=4 ...

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Order of a Differential Equation

Order and deg...

Question

Order and degree of the D.E ${[{(\frac{d y}{d x})}^{2} + \frac{d^{2} y}{d x^{2}}]}^{3 / 4} = K \frac{d^{3} y}{d x^{3}}$ is:

4,5

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5,3

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3,2

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3,4

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Solution

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{[1 + {(\frac{d y}{d x})}^{2}]}^{3 / 2} = 8 \frac{d^{2} y}{d x^{2}}

y = 1 + {(\frac{d y}{d x})}^{1} + \frac{1}{2!} {(\frac{d y}{d x})}^{2} + \frac{1}{3!} {(\frac{d y}{d x})}^{3} + . . . . .

\frac{d^{2} y}{d x^{2}} = x l o g (\frac{d y}{d x})

{[\frac{d^{2} y}{d x^{2}} + {(\frac{d y}{d x})}^{3}]}^{\frac{6}{5}} = 6 y

\frac{d^{2} y}{d x^{2}} + {(\frac{d y}{d x})}^{3} + 3 y = x^{2}

\frac{d^{2} y}{d x^{2}} + {(\frac{d y}{d x})}^{3 / 2} = y

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