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Byju's Answer
Standard XII
Chemistry
Gibbs Free Energy & Spontaneity
Order of boil...
Question
Order of boiling point and melting point of
Z
n
,
C
d
,
H
g
,
respectively is:
A
Z
n
>
C
d
>
H
g
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B
H
g
>
C
d
>
Z
n
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C
H
g
=
C
d
=
Z
n
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D
None of the above
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Solution
The correct option is
A
Z
n
>
C
d
>
H
g
Boiling point
Melting point
Z
n
1180
K
(
907
o
C
)
693
K
(
120
o
C
)
C
d
766.8
o
C
321
o
C
H
g
630
K
(
357
o
C
)
234
K
(
−
39
o
C
)
⇒
Z
n
,
C
d
,
H
g
don't have lone pair of electrons. So, there is no interaction with neighbour atoms. So, their melting point and boiling points are less.
∴
Z
n
>
C
d
>
H
g
for both boiling point & melting point.
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Similar questions
Q.
Boiling and melting point of Zn, Hg and Cd are low due to
Q.
Which of the comparison regarding
Z
n
,
C
d
,
H
g
is/are correct?
(I)
Z
n
C
l
2
is ionic whereas
C
d
C
l
2
and
H
g
C
l
2
are covalent.
(II)
Z
n
and
C
d
dissolves in dilute acid
(
H
C
l
)
liberating
H
2
whereas
H
g
do not.
(III)
Z
n
and
C
d
forms precipitate of
Z
n
(
O
H
)
2
and
C
d
(
O
H
)
2
but
H
g
forms coloured precipitate of
H
g
(
O
H
)
2
.
(IV) All forms
A
2
+
2
type ion.
Q.
Which of the following statements are correct about
Z
n
,
C
d
and
H
g
?
(
I
)
they exhibit high enthalpies of atomisation as the
d
-subshell is full
(
I
I
)
Z
n
and
C
d
do not show variable oxidation states while
H
g
shows
+
I
and
+
I
I
(
I
I
I
)
Compound of
Z
n
,
C
d
and
H
g
are paramagnetic in nature
(
I
V
)
Z
n
,
C
d
and
H
g
are called soft metals.
Q.
Assertion :Increasing order of covalent character among given compounds is
H
g
C
l
2
<
C
d
C
l
2
<
Z
n
C
l
2
. Reason: Order of size of cations is
Z
n
2
+
<
C
d
2
+
<
H
g
2
+
Q.
Assertion :Zn, Cd and Hg are not regarded as transition elements. Reason: The electronic configurations of Zn, Cd and Hg are represented by the general formula
(
n
−
1
)
d
10
n
s
2
.
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