Order of D-E- 1- d2ydx2 2- - 2- dydx -3-2 is-

The correct option is C 2 (1+y_2)^2=(2+y_1)^3 ⇒ y_2^4+2y_2^2+1=(2+y_1)^3 ⇒ Order=2 degree=4 ...

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Order of a Differential Equation

Order of D.E,...

Question

Order of D.E, $1 + {(\frac{d^{2} y}{d x^{2}})}^{2} = {[2 + (\frac{d y}{d x})]}^{3 / 2}$ is:

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{[1 + {(\frac{d y}{d x})}^{2}]}^{3 / 2} = {(\frac{d^{2} y}{d x^{2}})}^{2}

{1 + {(\frac{d y}{d x})}^{2}}^{\frac{1}{2}} = {(\frac{d^{2} y}{d x^{2}})}^{2}

[1 + {(\frac{d^{2} y}{d x^{2}})}^{2}] = {[2 + {(\frac{d y}{d x})}^{2}]}^{3 / 2}

\sqrt{1 + {(\frac{d y}{d x})}^{2}} = {(] \frac{d^{2} y}{d x^{2}})}^{\frac{2}{3}}

{(\frac{d^{2} y}{d x^{2}})}^{2} + {(\frac{d y}{d x})}^{3} + 3 y = x^{4}

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