Order of decreasing basic strength of halides is:

F^{-} > C l^{-} > I^{-} > B r^{-}

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F^{-} > C l^{-} > B r^{-} > I^{-}

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I^{-} > B r^{-} > C I^{-} > F^{-}

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I^{-} > C l^{-} > B r^{-} > F^{-}

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Solution

The correct option is C $F^{-} > C l^{-} > B r^{-} > I^{-}$
The order of acid strength is $H F < H C l < H B r < H I$
A stronger acid has weaker conjugate base and vice versa.
Hence, the order of the base strength will be exact opposite to that of acid strength.
Therefore, order of decreasing basic strength of halides is:
$F^{-} > C l^{-} > B r^{-} > I^{-}$

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Similar questions

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