Order of Migratory aptitude in Baeyer villiger oxidation is :

H > P h > 3^{o} > 2^{o} > 1^{o} > C H_{3}

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H > 3^{o} > 2^{o} > P h > 1^{o} > C H_{3}

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H > 3^{o} > P h > 2^{o} > 1^{o} > C H_{3}

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H > 3^{o} > 2^{o} > 1^{o} > P h > C H_{3}

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Solution

The correct option is B $H > 3^{o} > 2^{o} > P h > 1^{o} > C H_{3}$
In first step of Baeyer villiger oxidation, the oxygen atom of peroxy acid attacks the carbonyl compound to form a tertrahedral intermediate. In next step, there is a migration of group attached to ketone to the oxygen atom from peroxy acid.
The order of migratory aptitude in Baeyer villiger oxidation is
$H > 3^{o} > 2^{o} > P h > 1^{o} > C H_{3}$

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