Order of rate of electrophilic substitution reaction is:
A
Q>P>S>R
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B
Q>P>R>S
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C
P>Q>S>R
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D
P>Q>R>S
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Solution
The correct option is AQ>P>S>R Among the above compounds, P,R,S are amides therefore lone pair present on N will be delocalised, IN Q the nitrogen is directly attached to aromatic ring, which activates the ring, hence Q will have maximum reactivity.
In P, Nitrogen is no cross conjugation with benzene rings also, therefore effect of delocalization of lone pair will be minimised so P will have reactivity after Q.
In compound S, amide is isolated so the aromatic ring is not deactivated, hence, more reactive than R, therefore order of reactivity: