Order of reactivity is
$R_{2} C = C R_{2} < R_{2} C = C H R < R C H = C H R < C H_{2} = C H_{2}$

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Solution

According to saytzeff's rule, more substitute alkene is more stable or least reactive due to more $α - H$ or hyper conjugation effect.

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Similar questions

R_{2} C = C R_{2} I, R_{2} C = C H R I I, R_{2} C = C H_{2} I I I, R C H = C H R I V

R C H = C H_{2} V

R C H = C H R, R_{2} C = C H R

R_{2} C = {C R}_{2}

_{2}

_{2}

_{2}

_{2}

_{2}

_{2}

R - C \equiv ⊖ C

R_{2} C = ⊖ C H

R_{2} C - ⊖ C H_{2}

B L i n d l a r c a t a l y s t / H_{2} \leftarrow ----------- - R - C \equiv C - R N a / N H_{3} - ---- \to A

(R C H = C H R) .

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