Order the following elements according to increasing size $C s^{+}, B a^{2 +}, T e^{2 -}, X e I^{-}$
Don't worry about superscripts, enter $N^{3 -}$ as $N 3 -$ or $H^{+}$ as $H +$ .
Smallest $T e 2 < I - < X e < C s + < B a 2 +$ Largest.

Open in App

Solution

Increasing of order of size of element= $B a^{2 +} < C s^{2 +} < X e < I^{-} < T e^{2 -}$
On moving from left to right in a period size of element decreases while moving down the group size of element increases.
Moreover the size of cation is smaller than anion as in cation there is los of $e^{-}$ and in anion there is gain of $e^{-}$ and the size increases due to inter electronic repulsions.
$_{56} B a_{55} C s_{54} X e_{53} I_{52} T e$
$B a^{2 +} C s^{+} X e I^{-} T e^{2 -}$
no. of $e^{-} :$ $54$ $54$ $54$ $54$ $54$
no. of $p^{+} :$ $56$ $55$ $54$ $53$ $52$
more is the positive charge on the cation smaller is the size of cation and more in the negative charge on anion larger is the size. Hence the increasing order.

Suggest Corrections

Similar questions

A l^{3 +} < M g^{2 +} < N a^{+} < F^{-}

T e^{2 -} > I^{-} > C s^{+} > B a^{2 +}

F e^{3 +} < F e^{2 +} < F e^{4 +}

M g > A l > S i > P

N^{3 -}, N a^{+}, F^{-}, O^{2 -}, M g^{2 +}

O^{2 -}, S^{2 -}, N^{3 -}, P^{3 -}

Find the odd one out from the following and explain why? [5 MARKS]

{M g}^{2 +} < {N a}^{+} < F^{-} < O^{2 -} < N^{3 -}

Join BYJU'S Learning Program