Organic halogen compounds can be prepared by all the following methods except.

C H_{3} C H_{2} O H + H C l Z n C l_{2} \to

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C H_{3} - C H = C H_{2} S O_{3} C l_{2} \cdot 475 K \to

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C_{2} H_{5} O H + N a C l \to

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C H_{3} C O O A g + B r_{2} C C l_{4} \cdot R e f l u x \to

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Solution

The correct option is C $C_{2} H_{5} O H + N a C l \to$
Solution: As $C l^{-}$ comes in the category of weak nucleophile so it cannot displace $O H^{-}$ ion which falls in the category of the strong nucleophile.
So, in the third option no reaction will take place.
Hence, the correct option is (C).

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Organic halogen compounds can be prepared by all the following methods except.

The correct option is C C2H5OH+NaCl→Solution: As Cl− comes in the category of weak nucleophile so it cannot displace OH− ion which falls in the category of the strong nucleophile.So, in the third option no reaction will take place.Hence, the correct option is (C).

The correct option is C $C_{2} H_{5} O H + N a C l \to$
Solution: As $C l^{-}$ comes in the category of weak nucleophile so it cannot displace $O H^{-}$ ion which falls in the category of the strong nucleophile.
So, in the third option no reaction will take place.
Hence, the correct option is (C).