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Question

Orthocentre of a triangle with vertices (0,0),(3,4) and (4,0) is

A
(3,54)
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B
(3,12)
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C
(3,34)
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D
(3,9)
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Solution

The correct option is C (3,34)
We know that orthocentre is the point of intersection of altitudes of a Δ.





Equation of altitude AD
AD line is parallel to Y - axis through (3,4)
x=3 (1)
Similarly equation of OE is
y = - 3440x
y=x/4 (2)
Solving (1) and (2), we get orthocentre as (3,3/4).

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