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Osmotic Pressure

Osmotic press...

Question

Osmotic pressure of a solution is 0.0821 atm at a temperature of 400 K. Calculate the concentration of solution in mol/litre.
$[R = 0.0821 L a t m K^{- 1} m o l^{- 1}]$

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Solution

The osmotic pressure
$π = C R T$
$0.0821 a t m = C \times 0.0821 L a t m / K m o l \times 400 K$
$C = 0.0025 m o l / L$
Hence, the concentration of solution is 0.0025 mol/L.

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Osmotic pressure is 0.0821 atm at a temperature of 300 K. Find concentration in mole/litre.

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