Out of $1 s t 30$ natural numbers (i.e., $1$ to $30$ ) three are selected at random. The probability that they are not consecutive is

\frac{1}{145}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{144}{145}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{28}{145}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{2}{145}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $\frac{144}{145}$
Total ways of choosing three numbers $=^{30} C_{3}$
The ways of choosing consecutive numbers $= 28$
P (not consecutive) $= 1 - 28 / C (30, 3) = 144 / 145$

Suggest Corrections

Similar questions

Q. Out of the first 30 natural numbers (i.e., 1 to 30), three are selected at random. The probability that no two are together

Q. Find out the sum of all natural numbers between

1

and

145

which are divisible by

4

Q. Three numbers are chosen at random from

1

20

. The probability that they are consecutive is

Q. Out of

11

consecutive natural numbers if three numbers are selected at random (without repetition), then the probability that they are in A.P. with positive common difference, is:

The attendance report of a class for 150 days is as follows:

$\begin{matrix} Student & Attendance 1 & 146 2 & 142 3 & 147 4 & 149 5 & 146 6 & 145 7 & 147 8 & 146 9 & 145 10 & 150 11 & 143 12 & 145 13 & 144 14 & 142 15 & 148 \end{matrix}$

What is the probability that a student has 98% or more attendance?

Join BYJU'S Learning Program

Out of 1st 30 natural numbers (i.e., 1 to 30) three are selected at random. The probability that they are not consecutive is

The correct option is B 144145Total ways of choosing three numbers =30C3The ways of choosing consecutive numbers =28P (not consecutive) =1−28/C(30,3)=144/145

Out of $1 s t 30$ natural numbers (i.e., $1$ to $30$ ) three are selected at random. The probability that they are not consecutive is

The correct option is B $\frac{144}{145}$
Total ways of choosing three numbers $=^{30} C_{3}$
The ways of choosing consecutive numbers $= 28$
P (not consecutive) $= 1 - 28 / C (30, 3) = 144 / 145$