wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Out of 200 students who are trying to improve their vocabulary, 120 students read newspaper H, 50 read newspaper T and 30 read both newspaper H and T. find the number of students

i) who read H but not T

ii) who read T but not H

iii) who don't read any newspaper


A

30,20,60

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

90, 20, 60

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

90, 20, 30

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

20,30,60

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

90, 20, 60


Let U be universal set consisting of all students

Set A denote the students who read newspaper H.

Set B denote the students who read newspaper T.

Here n()=200, n(H)=120, n(T)=50, n(HT)=30

i) H but not T is nothing but H - T

Consider the Venn Diagram above.

H=(HT)(HT)

So, n(H)=n(HT)+n(HT)

(since H - T and HT are disjoint)

n(HT)=n(H)n(HT)

= 120 - 30 = 90

n(TH)=n(T)n(HT)

= 50 - 30 = 20

n(Who don't read any newspaper) =n()n(H)n(T)+n(HT)

= 200 - 120 - 50 +30 = 60


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Frequency Distribution Table
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon