Out of 2100 kg wheat, some part is sold making 10% profit while the remaining part is sold making 16% profit. If there is an overall profit of 14%, what quantity was sold at 16% profit?

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Solution

Let the $X$ $K g$ of wheat sold at 10℅ profit
Then $2100 - X$ $K g$ of wheat be sold at 16℅ profit
According to question, $X \times \frac{10}{100} +$ ( $2100 - X$ ) $\times \frac{16}{100} = 2100 \times \frac{14}{100}$
On solving it we get $X = 700$ and $2100 - X = 1400$
So, $1400$ $K g$ of wheat was sold at 14℅

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Out of 2100 kg wheat, some part is sold making 10% profit while the remaining part is sold making 16% profit. If there is an overall profit of 14%, what quantity was sold at 16% profit?

Let the X Kg of wheat sold at 10℅ profitThen 2100−X Kg of wheat be sold at 16℅ profitAccording to question,X×10100+(2100−X)×16100=2100×14100On solving it we get X=700 and 2100−X=1400So,1400 Kg of wheat was sold at 14℅