Out of 40 laptops that were given for service at a computer repair shop, 5 had an issue with the screen, 8 had an issue with the keyboard, 24 had software issues while the rest had multiple issues. What is the probability that a laptop given for service at the shop will have multiple issues?

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Solution

Probability of a laptop not having multiple issues = $\frac{5 + 8 + 13}{40}$ = $\frac{37}{40}$ = 0.925
Probability of a laptop having multiple issues = 1 – 0.925 = 0.075.

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Out of 40 laptops that were given for service at a computer repair shop, 5 had an issue with the screen, 8 had an issue with the keyboard, 24 had software issues while the rest had multiple issues. What is the probability that a laptop given for service at the shop will have multiple issues?

Probability of a laptop not having multiple issues = 5+8+1340 = 3740 = 0.925 Probability of a laptop having multiple issues = 1 – 0.925 = 0.075.

Probability of a laptop not having multiple issues = $\frac{5 + 8 + 13}{40}$ = $\frac{37}{40}$ = 0.925
Probability of a laptop having multiple issues = 1 – 0.925 = 0.075.