Out of 40 persons in a class, 10 play football, 15 play cricket, 5 play both football and cricket. How many of them plays neither football nor cricket?
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Solution
N(F)=People playing football. =10 N(C) =Peple playing cricket = 15 N(F∪C) = People playing either football or cricket N(F∩C) People playing both =5 N(F∪C)=N(F)+N(C)−N(F∩C) =10+15-5 =20 People playing reither football nor cricket = 40-20=20