Out of 5 men and 3 women, a committee of 3 members is to be formed such that it has 1 woman and 2 men.In how many different ways can it be done?
A
20
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B
10
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C
30
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D
None of these
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Solution
The correct option is C 30 Number of selection = Number of ways of selecting 2 men out of 5 men × number of ways of selecting 1 woman out of 3 women. =5C2×3C1=5×41×2×3=30