Question

Out of 5 men and 3 women, a committee of 3 members is to be formed so that it has 1 woman and 2 men. In how many different ways can it be done?

• A. 20
• B. 10
• C. 23
• D. 30
• E. None of these

Answer 1

The correct option is D 30

Number of selections = Number of ways of selecting 2 men out of 5 men $\times$ Number of ways of selecting 1 woman out of 3 women
$={}^5{C}_2\times {}^3{C}_1=\frac{5\times 4}{1\times 2}\times 3=30$