Out of 50 questions in a test, Jenny answered $78 %$ of them correctly. Each correct answer carries 3 marks and each wrong answer carries a negative marking of one mark. She did not answer 6 questions for which she will neither gain nor lose any mark. Calculate the total marks she scored.

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Solution

$78 % o f 50 = \frac{78}{100} \times 50 = 39$
So, Mark for correct answer $= 3 \times 39$
No. of wrong question = 50 - (39 + 6) = 5
Unattempted question = 6
So, mark obtained $= 39 \times 3 - 5 \times 1$
=117 - 5 = 112

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Out of 50 questions in a test, Jenny answered 78% of them correctly. Each correct answer carries 3 marks and each wrong answer carries a negative marking of one mark. She did not answer 6 questions for which she will neither gain nor lose any mark. Calculate the total marks she scored.

78% of 50=78100×50=39 So, Mark for correct answer =3×39 No. of wrong question = 50 - (39 + 6) = 5 Unattempted question = 6 So, mark obtained =39×3−5×1 =117 - 5 = 112

Out of 50 questions in a test, Jenny answered $78 %$ of them correctly. Each correct answer carries 3 marks and each wrong answer carries a negative marking of one mark. She did not answer 6 questions for which she will neither gain nor lose any mark. Calculate the total marks she scored.

$78 % o f 50 = \frac{78}{100} \times 50 = 39$
So, Mark for correct answer $= 3 \times 39$
No. of wrong question = 50 - (39 + 6) = 5
Unattempted question = 6
So, mark obtained $= 39 \times 3 - 5 \times 1$
=117 - 5 = 112