Out of 6 green balls, 4 blue balls, in how many ways can we select one or more balls ?

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None of these

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Solution

The correct option is B 34
7 $\times$ 5 = 35
35 - 1 = 34

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Out of 6 green balls, 4 blue balls, in how many ways can we select one or more balls ?

The correct option is B 347 × 5 = 35 35 - 1 = 34

The correct option is B 34
7 $\times$ 5 = 35
35 - 1 = 34