Out of a population of 800 individuals in F2 generation of a cross between yellow round and green wrinkled pea plant, what would be the number of yellow and wrinkled seeded plants?
A
800
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B
400
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C
200
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D
150
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Solution
The correct option is D 150 In pea plant, yellow seed color is dominant over green and round seed shape is dominant over wrinkled shape. A cross between yellow round (YYRR) and green wrinkled (yyrr) pea plant gives all yellow round (YyRr) plants in F1 generation. Selfing of yellow round (YyRr) plants produce F2 generation with 9 yellow round (YYRR) : 3 yellow wrinkled : 3 green round : 1 green wrinkled plants. Thus, out of a population of 800 individuals in F2$ generation number of yellow and wrinkled seeded plants is 3/16 x 800 = 150. Thus, the correct answer is option D.