Out of Be2+, Mg+ and Ca, Be2+ has maximum IE.
If true enter 1, else enter 0.
If true enter 1, else enter 0.
The
ionization energy (IE) of the element M is a measure of the energy required to
remove one electron from one mole of the gaseous atoms M. IE is affected by size, effective
nuclear charge, type of orbital from which the electron is being removed and
electronic configuration. So, it decreases while moving down the group.
Be,
Mg, and Ca belong to the second group of the periodic table. All of them can
lose 2 electrons to attain a stable state. So, Be being the smallest of all has
the maximum IE. Also, when it loses 2 electrons to become Be2+, energy required
to remove 1 more electron after achieving the stable state is very high. Mg,
when loses 1 electron to become Mg+, its size decreases so, the 2nd IE required to remove 1 more electron is
higher. Ca has the lowest IE as its size is bigger as compared to the other two and also, it has 2 electrons to lose to achieve a stable state.
Hence, the statement is correct.
The ionization energy (IE) of the element M is a measure of the energy required to remove one electron from one mole of the gaseous atoms M. IE is affected by size, effective nuclear charge, type of orbital from which the electron is being removed and electronic configuration. So, it decreases while moving down the group.
Be, Mg, and Ca belong to the second group of the periodic table. All of them can lose 2 electrons to attain a stable state. So, Be being the smallest of all has the maximum IE. Also, when it loses 2 electrons to become Be2+, energy required to remove 1 more electron after achieving the stable state is very high. Mg, when loses 1 electron to become Mg+, its size decreases so, the 2nd IE required to remove 1 more electron is higher. Ca has the lowest IE as its size is bigger as compared to the other two and also, it has 2 electrons to lose to achieve a stable state.
Hence, the statement is correct.
