out of cards numbered from 1 to 20, which are mixed thoroughly ,a card is drawn at random find the probability that the drawn card bears a numbers which is a multiple of 3 or 7.

Open in App

Solution

Multiples of 3 0r 7 fro 1 to 20 are $3, 6, 7, 9, 12, 14, 15, 18$ .

Therefore, required probability, P = $\frac{8}{20} = \frac{2}{5}$ .

Suggest Corrections

Similar questions

Q. 17 cards numbered 1, 2, 3, 4, .... ,17 are put in a box and mixed thoroughly. A card is drawn at random from the box. Find the probability that the card drawn bears (i) an odd number (ii) a number divisible by 5.

Q. Cards marked with number

3, 4, 5............, 50

are placed in a box and mixed thoroughly. A card is drawn at random from the box. Find the probability that the selected card bears a perfect square number.

A bag contains cards numbers from 1 to 49. A card is drawn from the bag at random, after mixing the cards thoroughly. Find the probability that the number on the drawn card is:
(1) An odd number
(2) A multiple of 5
(3) A perfect Square
(4) An even prime number

Q. Cards bearing numbers

3

19

are put in a box and mixed thoroughly. A card is drawn from the box at random. Find the probability that the number on the card drawn is

(i)

Even

(i i)

A prime

(i i i)

Divisible by

2

and

3

both.

Cards bearing numbers 3 to 20 are placed in a bag and mixed thoroughly. A card is taken out from the bag at random. What is the probability that the number on the card taken out is an even number ?

Join BYJU'S Learning Program

out of cards numbered from 1 to 20, which are mixed thoroughly ,a card is drawn at random find the probability that the drawn card bears a numbers which is a multiple of 3 or 7.

Multiples of 3 0r 7 fro 1 to 20 are 3,6,7,9,12,14,15,18.Therefore, required probability, P = 820=25.

Multiples of 3 0r 7 fro 1 to 20 are $3, 6, 7, 9, 12, 14, 15, 18$ .

Therefore, required probability, P = $\frac{8}{20} = \frac{2}{5}$ .