Out of $F e^{2 +}, F e^{3 +}, M n^{2 +}$ and $T i^{2 +}$ , the least size is of:

M n^{2 +}

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T i^{2 +}

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F e^{2 +}

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F e^{3 +}

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Solution

The correct option is C $F e^{3 +}$
${F e}^{3 +}$ will have least size.The nuclear pull which is present on the atom which makes the atom lesser in size.Other than all having greater atomic size when compared with the ${F e}^{3 +}$ .

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E^{\circ}

for the half cells :

M n O_{2} + 4 H^{+} + 2 e^{-} \to M n^{2 +} + 2 H_{2} O i s 1.23 V F e^{3 +} + e^{-} \to F e^{2 +} i s 0.77 V

Which of the following statements is true?

While $F e^{3 +}$ is stable, $M n^{3 +}$ is not stabe in acid solution because:
$(M n^{3 +} + e^{-} \to M n^{2 +}, E^{\circ} = 1.5 V; O_{2} + 4 H^{+} + 4 e^{-} \to 2 H_{2} O, E^{\circ} = + 1.23 V; F e^{3 +} + e^{-} \to F e^{2 +}, E^{\circ} = 0.77 V)$

The balanced equation in basic medium is :

M n O_{4} + F e^{2 +} O H^{-} \to M n^{2 +} + F e^{3 +}

Q. Consider the ions

F e^{2 +}, F e^{3 +}, C r^{2 +}, C r^{3 +}, M n^{2 +}, M n^{3 +}

. Strongest oxidizing ion is ?

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Out of Fe2+,Fe3+,Mn2+ and Ti2+, the least size is of:

The correct option is C Fe3+Fe3+ will have least size.The nuclear pull which is present on the atom which makes the atom lesser in size.Other than all having greater atomic size when compared with the Fe3+.

Out of $F e^{2 +}, F e^{3 +}, M n^{2 +}$ and $T i^{2 +}$ , the least size is of:

The correct option is C $F e^{3 +}$
${F e}^{3 +}$ will have least size.The nuclear pull which is present on the atom which makes the atom lesser in size.Other than all having greater atomic size when compared with the ${F e}^{3 +}$ .