Out of [Fe(CN)6]4−,[Ni(CN)4]2− and [Ni(CO)4] :
A
all have identical geometry
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B
all are paramagnetic
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C
all are diamagnetic
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D
[Fe(CN)6]4− is diamagnetic but [Ni(CN)4]2− and [Ni(CN)4] are paramagnetic
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Solution
The correct option is C all are diamagnetic As CN− and CO both are strong ligand so in presence of these ligands, pairing of electron happens. So they all compounds dont have unpaired electron and they all are diamagnetic.