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Byju's Answer
Standard XII
Chemistry
Relating Translational KE and T
Out of H 2, C...
Question
Out of
H
2
,
C
O
,
N
2
and
C
O
2
,
the gas which has least mean free path is:
A
has maximum value of a (van der Waals' constant)
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B
is easily liquefied
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C
has maximum value of
(Boyle's temperature)
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D
for all of the above cases
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Solution
The correct option is
B
is easily liquefied
When a heavier gas, is reploud with a lighter gas the mean gra path mcrcases under similar conditions
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Similar questions
Q.
The value of van der Waals constant
a
for the gases
O
2
,
N
2
,
N
H
3
,
a
n
d
C
H
4
are 1.360, 1.390, 4.170, and
2.253
L
2
a
t
m
m
o
l
−
2
, respectively.
Which gas can most easily be liquefied?
Q.
The van der Waals’ constants for a gas are;
a
=
3.6
atm L
2
mol
2
,
b
=
0.6
L mol
−
1
. If
R
=
0.08
L atm K
−
1
. If the Boyle's temperature
(
K
)
of this gas is
T
B
, then what is the value of
T
B
15
?
Q.
The van der Waals’ constants for a gas are;
a
=
3.6
atm L
2
mol
2
,
b
=
0.6
L mol
−
1
. If
R
=
0.08
L atm K
−
1
. If the Boyle's temperature
(
K
)
of this gas is
T
B
, then what is the value of
T
B
15
?
Q.
The numerical value of '
a
' the van der Waals' constant is maximum for:
Q.
Which has maximum value of mean free path?
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