Out of Na+,Mg+2,O−2 and N−3, the pair of species having the minimum and the maximum IP would be?
A
Na+,Mg+2
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B
Mg+2,N−3
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C
N−3,Mg+2
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D
O−2,N−3
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Solution
The correct option is CN−3,Mg+2 It is easier to remove electron from negative species and difficult to remove electron from positive species. Thus its easiest to remove electron from N3− and difficult for Mg2+