Question

Out of $N{a}^{+}$, $M{g}^{+2},O^{-2}$ and $N^{-3}$, the pair of species showing minimum and maximum I.P would be:

• A. $N{a}^{+},M{g}^{+2}$
• B. $M{g}^{+2},N^{-3}$
• C. $N^{-3}.M{g}^{+2}$
• D. $O^{-2},N^{-3}$

Answer 1

The correct option is C $N^{-3}.M{g}^{+2}$

The term ionization potential is an older name for ionization energy. It means the amount of energy required to remove most loosely bound electron, the valence electron, of an isolated neutral gaseous atom, molecule or ion. In the given elements the number of electrons is the same i.e, 10. Hence, More is the nuclear charge more is the more is the I.P. In the given elements $M{g}^{+2}$ has the highest nuclear charge and $N^{3-}$ has the lowest nuclear charge.

Minimum IP is shown by $N^{3-}$

Maximum IP is shown by $M{g}^{+2}$

Therefore option (C) is correct