Out of $N H_{3}, P H_{3}$ and $A s H_{3}$ boiling point of $N H_{3}$ is maximum and that of $P H_{3}$ is minimum.
If true enter 1, else enter 0.
1

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Solution

The correct option is A 1
Ammonia forms hydrogen bonds woth water which makes its boiling point higher. This happens due to presence of lone pair.

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Similar questions

A s H_{3} < P H_{3} < N H_{3}

N H_{3} > P H_{3} > A s H_{3} > S b H_{3} > B i H_{3}

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

N H_{3}

P H_{3}

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

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