Out of the following compounds, I. Pent-1-ene, II. Pent-2-ene, III. 2-Methyl but-1-ene IV. 2-Methyl but-2-ene,
Which pair has the lowest and the highest heats of combustion, respectively?
A
(IV) and (I), respectively
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B
(I) and (IV), respectively
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C
(II) and (III), respectively
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D
(III) and (II), respectively
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Solution
The correct option is A (IV) and (I), respectively
IV. 2-Methyl but-2-ene has the lowest heat of combustion. I. Pent-1-ene has the highest heat of combustion. More-stable or more-substituted alkene has the lowest (more negative) heat of combustion, formation and hydrogenation.
Thus, the order of stability of alkenes is IV > III > II > I.