Question

Out of the following compounds, which is the most basic in aqueous solution?

• A. ${CH}_3{NH}_2$
• B. ${\left({CH}_3\right)}_{2}NH$
• C. ${\left({CH}_3\right)}_{3}N$
• D. $C_6{H}_5{NH}_2$

Answer 1

The correct option is B ${\left({CH}_3\right)}_{2}NH$

$(C{H}_3{)}_{2}NH$ is the most basic compound out of the compounds given.

The explanation is as follows :
It is more basic than $C{H}_{3}N{H}_2$ because of one more methyl group that increases basicity by $+I$ effect.

But a number of factors count into basicity.
One of the important ones being the solvation effect.

In $N(C{H}_3{)}_3$, due to excess steric hinderance, the solvation of the resulting ion is reduced. So, the conjugate acid is not much stabilized. So, it is less basic.

Option B is correct.