Out of the following, the alkene that exhibits optical isomerism is:
A
3-methyl-2-pentene
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B
4-methyl-1-pentene
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C
3-methyl-1-pentene
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D
2-methyl-2-pentene
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Solution
The correct option is C 3-methyl-1-pentene As, C∗ has 4 different groups attached to it, so it is a chiral carbon. so, above compound is optically active.