Question

Out of the molecules given below,
$\left(i\right)C_2{H}_4\left(ii\right)AlC{l}_3\left(iii\right)C{H}_4\left(iv\right)N{F}_3$
Which molecules have same hybridisation:

• A. $\left(i\right),\left(iii\right)$
• B. $\left(i\right),\left(ii\right),\left(iv\right)$
• C. $\left(i\right),\left(iii\right),\left(iv\right)$
• D. $\left(iii\right),\left(iv\right)$

Answer 1

The correct option is D $\left(iii\right),\left(iv\right)$

The compounds having same hybridisation of the central atom will have same geometry though their shape may be different.

(i) In $C_2{H}_4$, both the $C$ atoms has zero lone pairs of electrons and two bonds with two hydrogen atoms and $1$ bond with another carbon. Thus, it is $s{p}^2$ hybridised.
(ii) In $AlC{l}_3$ , $Al$ is bonded to three $H$ atom without any lone pair. Thus, it is $s{p}^2$ hybridised.
(iii) In $C{H}_4$, $C$ is bonded to four $H$ atoms. Thus, it $s{p}^3$ hybridised.
(iv) In $N{F}_3$, $N$ atom is bonded to three $F$ atoms and has one lone pair. Thus, it is also $s{p}^3$ hybridised.
Thus, $C{H}_4$ and $N{F}_3$ have same hybridisation i.e., $s{p}^3$.