Question

Out of three positive numbers, the ratio of the first and the second is 10:11 and that of the second and third is 1:2 .
Find the three numbers if the product of the first and the second is 2750 .

• A. 50
• B. 55
• C. 11
• D. 110

Answer 1

Answer: (A), (B), (D)

The correct options are
A

50

B

55

D

110

$1^{st}\text{Number}:2^{nd}\text{Number}=10:11;2^{nd}\text{Number}:3^{rd}\text{Number}=1:2=11:22$
$\text{So the ratio of}{1}^{st}\text{Number},2^{nd}\text{Number}\text{and}{3}^{rd}\text{Number is}$
$1^{st}\text{Number}:2^{nd}\text{Number}:3^{rd}\text{Number = 10 : 11 : 22}$
$\text{Let the}{1}^{st}\text{Number},2^{nd}\text{Number and}{3}^{rd}\text{Number be}$
$\text{(10x), (11x) and (22x) respectively where x is any positive number.}$
$\text{Accordding to the problem :}$
$1^{st}\text{Number}\times 2^{nd}\text{Number = 2750}$
$\text{(10x)}\times \text{(11x) = 2750 or}110x^2=\text{2750}$
$\text{By solving we get x = 5}$
$\text{The three numbers are 50, 55, 110.}$