Question

# Out of $$TiF^{2-}_6, CoF^{3-}_6, CuCl_2$$ and $$NiCl^{2-}_4$$ (Z of Ti = 23, Co = 27, Cu = 29,Ni = 28), the colourless species are:

A
TiF26,CoF36
B
Cu2Cl2,NiCl24
C
TiF26,Cu2Cl2
D
CoF36,NiCl24

Solution

## The correct option is B $$TiF^{2-}_6, Cu_2Cl_2$$Oxidation state of Ti  in $$TiF^{2-}_6= Ti^{4+} = [Ne] 3s^23p^6$$ (No unpaired electron).Oxidation state of Cu in $$Cu_2Cl_2 = Cu^+ = [Ar]3d^{10}$$ (No unpaired electron). Due to absence of unpaired electron both are colourless. Hence, option C is correct.Chemistry

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