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Question

Out of TiF2−6,CoF3−6,CuCl2 and NiCl2−4 (Z of Ti = 23, Co = 27, Cu = 29,Ni = 28), the colourless species are:

A
TiF26,CoF36
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B
Cu2Cl2,NiCl24
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C
TiF26,Cu2Cl2
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D
CoF36,NiCl24
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Solution

The correct option is B TiF26,Cu2Cl2
Oxidation state of Ti in TiF26=Ti4+=[Ne]3s23p6
(No unpaired electron).
Oxidation state of Cu in Cu2Cl2=Cu+=[Ar]3d10
(No unpaired electron).
Due to absence of unpaired electron both are colourless.
Hence, option C is correct.

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