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Question

|¯¯¯a.¯¯b|2+|¯¯¯aׯ¯b|2=

A
ab
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B
a/b
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C
a2/b2
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D
a2b2
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Solution

The correct option is D a2b2
|¯¯¯a.¯¯b|2+|¯¯¯aׯ¯b|2 =|ab|2(sin2θ+cos2θ)=a2b2

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