$¯ ¯ ¯ a, ¯ ¯ b, ¯ ¯ c$ , are position vectors of the vertices of a triangle $A B C$ . The length of the perpendicular drawn from $C$ to $A B$ is

\frac{| ¯ ¯ ¯ a \times ¯ ¯ b + ¯ ¯ b \times ¯ ¯ c + ¯ ¯ c \times ¯ ¯ ¯ a |}{| ¯ ¯ ¯ a - ¯ ¯ b |}

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\frac{| ¯ ¯ ¯ a \times ¯ ¯ b + ¯ ¯ b \times ¯ ¯ c + ¯ ¯ c \times ¯ ¯ ¯ a |}{| ¯ ¯ b - ¯ ¯ c |}

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\frac{| ¯ ¯ ¯ a \times ¯ ¯ b + ¯ ¯ b \times ¯ ¯ c + ¯ ¯ c \times ¯ ¯ ¯ a |}{| ¯ ¯ ¯ a - ¯ ¯ c |}

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| ¯ ¯ ¯ a \times ¯ ¯ b + ¯ ¯ b \times ¯ ¯ c + ¯ ¯ c \times ¯ ¯¯¯¯¯ ¯ - a |

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Solution

The correct option is D $\frac{| ¯ ¯ ¯ a \times ¯ ¯ b + ¯ ¯ b \times ¯ ¯ c + ¯ ¯ c \times ¯ ¯ ¯ a |}{| ¯ ¯ ¯ a - ¯ ¯ b |}$
Length of the $⊥$ from to $A B$
$∣ ∣ (\to c - \to a) \times (\to a - \to b) ∣ ∣$
$\frac{| (\to c - \to a) \times (\to a - \to b) |}{| \to b - \to a |}$
$\frac{| \to c \times \to a - \to c \times \to b + \to a \times \to b |}{| \to a - \to b |}$
$\frac{| \to c \times \to a + \to b \times \to c + \to a \times \to b |}{| \to a - \to b |}$

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Similar questions

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¯¯¯a, ¯¯b, ¯¯c, are position vectors of the vertices of a triangle ABC. The length of the perpendicular drawn from C to AB is

The correct option is D |¯¯¯a×¯¯b+¯¯b×¯¯c+¯¯c×¯¯¯a||¯¯¯a−¯¯b| Length of the ⊥ from to AB∣∣(→c−→a)×(→a−→b)∣∣|(→c−→a)×(→a−→b)||→b−→a||→c×→a−→c×→b+→a×→b||→a−→b||→c×→a+→b×→c+→a×→b||→a−→b|

$¯ ¯ ¯ a, ¯ ¯ b, ¯ ¯ c$ , are position vectors of the vertices of a triangle $A B C$ . The length of the perpendicular drawn from $C$ to $A B$ is