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Byju's Answer
Standard VIII
Mathematics
Properties of Angles Formed by Two Parallel Lines and a Transversal
PQ is perpend...
Question
¯
¯¯¯¯¯¯
¯
P
Q
is perpendicular to
¯
¯¯¯¯¯¯
¯
R
S
is symbolically written as ______.
A
¯
¯¯¯¯¯¯
¯
P
Q
⊥
¯
¯¯¯¯¯¯
¯
R
S
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B
¯
¯¯¯¯¯¯
¯
P
Q
∥
¯
¯¯¯¯¯¯
¯
R
S
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C
¯
¯¯¯¯¯¯
¯
P
Q
≠
¯
¯¯¯¯¯¯
¯
R
S
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D
¯
¯¯¯¯¯¯
¯
P
Q
=
¯
¯¯¯¯¯¯
¯
R
S
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Solution
The correct option is
A
¯
¯¯¯¯¯¯
¯
P
Q
⊥
¯
¯¯¯¯¯¯
¯
R
S
⊥
represents Perpendicularity.
Here Line
P
Q
is perpendicular to Line
R
S
∴
¯
¯¯¯¯¯¯
¯
P
Q
⊥
¯
¯¯¯¯¯¯
¯
R
S
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0
Similar questions
Q.
↔
P
Q
is perpendicular to
↔
R
S
is symbolically written as
Q.
Assertion :Let the vectors
P
Q
,
Q
R
,
R
S
,
S
T
,
T
U
and
U
P
represent the sides the regular hexagon
P
Q
×
(
R
S
+
S
T
)
≠
0
Reason:
P
Q
×
R
S
=
0
and
P
Q
×
S
T
≠
0
Q.
Observe the figure given.
Which of the following is true if PQ = RS?
Q.
Assertion :Let the vectors
−
−
→
P
Q
,
−
−
→
Q
R
,
−
−
→
R
S
,
−
→
S
T
,
−
−
→
T
U
and
−
−
→
U
P
represent the sides of a regular hexagon,
−
−
→
P
Q
×
(
−
−
→
R
S
+
−
→
S
T
)
≠
→
0
Reason:
−
−
→
P
Q
×
−
−
→
R
S
=
→
0
,
−
−
→
P
Q
×
−
→
S
T
≠
0
Q.
In Figure, common tangents
P
Q
and
R
S
to two circles intersect at
A
. Prove that
P
Q
=
R
S
.
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