1
Question
→A=3^i+2^j+7^k
→B=^i−6^j+5^k
→C=−2^i+^j−4^k
Find 2→A−→B+3→C
→A=3^i+2^j+7^k
→B=^i−6^j+5^k
→C=−2^i+^j−4^k
Find 2→A−→B+3→C
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Solution
The correct option is A
2→A=2(3^i+2^j+7^k)=6^i+4^j+14^k
−→B=^i+6^j−5^k
3→C=3(−2^i+^j−4^k)
=−6^i+3^j−12^k
2→A−→B+3→C=6^i+4^j+14^k+^i+6^j−5^k−6^i+3^j−12^k
=−^i+13^j−3^k
2→A=2(3^i+2^j+7^k)=6^i+4^j+14^k
−→B=^i+6^j−5^k
3→C=3(−2^i+^j−4^k)
=−6^i+3^j−12^k
2→A−→B+3→C=6^i+4^j+14^k+^i+6^j−5^k−6^i+3^j−12^k
=−^i+13^j−3^k
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