A is a vector which when added to the resultant of vectors 2-3-4k- and -5-2k- yields a unit vector along the y-axis- Then vector A is

As per the question, A+(2î 3ĵ+4k̂)+(î+5ĵ+2k̂)=ĵ ⇒A+3î+2ĵ+6k̂=ĵ ⇒A = 3î ĵ 6k̂ Hence, the correct option is (a). ...

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Byju's Answer

Standard XI

Physics

Addition and Subtraction in Unit Vector Notation

A is a vector...

Question

$\to A$ is a vector which when added to the resultant of vectors $(2^i - 3^j + 4^k)$ and $(^i + 5^j + 2^k)$ yields a unit vector along the y-axis. Then vector $\to A$ is

$- 3^i -^j - 6^k$

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$3^i +^j -^k$

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$- 3^i -^j + 6^k$

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$3^i +^j + 6^k$

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Solution

The correct option is A
$- 3^i -^j - 6^k$

As per the question, $\to A + (2^i - 3^j + 4^k) + (^i + 5^j + 2^k) =^j$
$\Rightarrow \to A + 3^i + 2^j + 6^k =^j$
$\Rightarrow \to A = - 3^i -^j - 6^k$
Hence, the correct option is (a).

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Similar questions

$\to A$ is a vector which when added to the resultant of vectors $(2^i - 3^j + 4^k)$ and $(^i + 5^j + 2^k)$ yields a unit vector along the y-axis. Then vector $\to A$ is

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→A is a vector which when added to the resultant of vectors (2^i−3^j+4^k) and (^i+5^j+2^k) yields a unit vector along the y-axis. Then vector →A is

The correct option is A −3^i−^j−6^k As per the question, →A+(2^i−3^j+4^k)+(^i+5^j+2^k)=^j ⇒→A+3^i+2^j+6^k=^j ⇒→A=−3^i−^j−6^k Hence, the correct option is (a).

$\to A$ is a vector which when added to the resultant of vectors $(2^i - 3^j + 4^k)$ and $(^i + 5^j + 2^k)$ yields a unit vector along the y-axis. Then vector $\to A$ is

The correct option is A
$- 3^i -^j - 6^k$

As per the question, $\to A + (2^i - 3^j + 4^k) + (^i + 5^j + 2^k) =^j$
$\Rightarrow \to A + 3^i + 2^j + 6^k =^j$
$\Rightarrow \to A = - 3^i -^j - 6^k$
Hence, the correct option is (a).