A -b -c are noncoplanar vectors and p -p -r as defined as p - b-c-bca - q - c-a-cab - r - a-b-abc - a - b -p - b - c -q - c - a -r is equal to

The correct option is B 3 (a+b) · #160; (b+c)[bca]+(b+c)·(c×a)[cab]+ (c+a)·(a×b)[abc] =a· (b×c)[bca]+0+b· (c×d)[cab]+0+c· (a×b)[abc]+0 =[ ...

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Scalar Triple Product

a ,b ,c are n...

Question

$\to a, \to b, \to c$ are noncoplanar vectors and $\to p, \to p, \to r$ as defined as
$\to p = \frac{\to b \times \to c}{[\to b \to c \to a]}, \to q = \frac{\to c \times \to a}{[\to c \to a \to b]}, \to r = \frac{\to a \times \to b}{[\to a \to b \to c]}, (\to a + \to b) . \to p + (\to b + \to c) . \to q + (\to c + \to a) . \to r$ is equal to

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Similar questions

\to a, \to b, \to c

\to p, \to q, \to r

\to p = \frac{\to b \times \to c}{[\to a \to b \to c]}, \to q = \frac{\to c \times \to a}{[\to a \to b \to c]}, \to r = \frac{\to a \times \to b}{[\to a \to b \to c]}

(\to a + \to b) . \to p + (\to b + \to c) . \to q + (\to c + \to a) . \to r

a, b

c

p, q

r

p = \frac{b \times c}{a b c}, q = \frac{c \times a}{a b c}

r = \frac{a \times b}{a b c}

(a + b) . p + (b + c) . q + (c + a) . r

\to a, \to b, \to c

\to p = \frac{\to b \times \to a}{[\to a \to b \to c]}, \to q = \frac{\to c \times \to a}{[\to a \to b \to c]}, \to r = \frac{\to a \times \to b}{[\to a \to b \to c]}

(\to a + \to b) . \to p + (\to b + \to c) . \to q + (\to c + \to a) . \to r =

a, b, c \in + R

a + b + c = p

\frac{b c}{a} + \frac{c a}{b} + \frac{a b}{c} \geq p

a, b

c

p, q

r

p = \frac{b \times c}{[a b c]}, q = \frac{c \times a}{[a b c]},

r = \frac{a \times b}{[a b c]},

(a + b) \cdot p + (b + c) \cdot q + (c + a) \cdot r

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