-AB and -CD intersect each other at point E- m- BED - 145- then find the measure of remaining angles-

By supplementary pair, m∠ AED = 180^∘ 145^∘ = 35^∘. m∠ AEC = 145^∘ ( ∵ it is vertically opposite to m∠ BED. ) ∠ BEC = 35^∘ ( ∵ ...

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Byju's Answer

Standard VII

Mathematics

Equal Angles Subtend Equal Sides

↔AB and ↔CD...

Question

$\leftrightarrow A B$ and $\leftrightarrow C D$ intersect each other at point $E$ . $m ∠ B E D = 145^{\circ}$ , then find the measure of remaining angles.

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Solution

By supplementary pair, $m ∠ A E D = 180^{\circ} - 145^{\circ} = 35^{\circ} .$
$m ∠ A E C = 145^{\circ}$ ( $∵$ it is vertically opposite to $m ∠ B E D .$ )
$∠ B E C = 35^{\circ}$ ( $∵$ it is vertically opposite to $m ∠ A E D .$ )

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↔AB and ↔CD intersect each other at point E. m∠BED=145∘, then find the measure of remaining angles.

By supplementary pair, m∠AED=180∘−145∘=35∘.m∠AEC=145∘ (∵ it is vertically opposite to m∠BED. )∠BEC=35∘ (∵ it is vertically opposite to m∠AED. )

$\leftrightarrow A B$ and $\leftrightarrow C D$ intersect each other at point $E$ . $m ∠ B E D = 145^{\circ}$ , then find the measure of remaining angles.

By supplementary pair, $m ∠ A E D = 180^{\circ} - 145^{\circ} = 35^{\circ} .$
$m ∠ A E C = 145^{\circ}$ ( $∵$ it is vertically opposite to $m ∠ B E D .$ )
$∠ B E C = 35^{\circ}$ ( $∵$ it is vertically opposite to $m ∠ A E D .$ )