N H 3- CH R - CO 2 H has its K a 1-10-7- The isoelectric point of the - amino acid occur at pH -8-2 hence pK a 2 of the conjugate acid of - - amino acid is equal to-A- 1-2B- 7-6C- 2-4D- 9-4

The correct option is D 9.4Isoelectric point is given by, pI= pKa_1 + pKa_22 ∴ 8.2 = 7+pKa_22 ⇒ pKa_2 = 16.4 7 =9.4 ...

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Byju's Answer

Standard XII

Biology

Types of Amino Acids

N H 3- CH R -...

Question

$+ N H_{3} - C H (R) - C O_{2} H$ has its $K a_{1} = 10^{- 7}$ . The isoelectric point of the $α -$ amino acid occur at $p H = 8.2$ hence $p K a_{2}$ of the conjugate acid of $α -$ amino acid is equal to:

9.4

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Solution

The correct option is A 9.4
Isoelectric point is given by, $p I = \frac{p K a_{1} + p K a_{2}}{2}$
$∴ 8.2 = \frac{7 + p K a_{2}}{2}$
$\Rightarrow p K a_{2} = 16.4 - 7 = 9.4$

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^{+} N H_{3} - C H (R) - C O_{2} H

has its

K a_{1} = 10^{- 7}

. The isoelectric point of the

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p K a_{2}

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+NH3−CH(R)−CO2H has its Ka1=10−7. The isoelectric point of the α− amino acid occur at pH=8.2 hence pKa2 of the conjugate acid of α− amino acid is equal to:

The correct option is A 9.4Isoelectric point is given by, pI=pKa1+pKa22 ∴8.2=7+pKa22 ⇒pKa2=16.4−7=9.4

$+ N H_{3} - C H (R) - C O_{2} H$ has its $K a_{1} = 10^{- 7}$ . The isoelectric point of the $α -$ amino acid occur at $p H = 8.2$ hence $p K a_{2}$ of the conjugate acid of $α -$ amino acid is equal to:

The correct option is A 9.4
Isoelectric point is given by, $p I = \frac{p K a_{1} + p K a_{2}}{2}$
$∴ 8.2 = \frac{7 + p K a_{2}}{2}$
$\Rightarrow p K a_{2} = 16.4 - 7 = 9.4$